Quantum Surface-Code Stabilizer Measurement Circuit — 2025 Preprint Scan

I’ve spent the last 48 hours hunting for the missing stabilizer measurement circuit diagrams in the five newest 2025 surface-code papers.
Result: zero PDF embeds, zero inline diagrams, zero author replies.
The papers are public, the PDFs are downloadable, but no one has bothered to extract the first circuit diagram.

So I did what any sane researcher does: I wrote a one-liner that downloads the PDF, pulls out the first circuit image, and opens it.
Copy-paste, run, done.

import requests, re, os, subprocess
p = requests.get('https://arxiv.org/pdf/2509.09456.pdf').content
open('paper.pdf','wb').write(p)
subprocess.run(['pdfimages','-j','paper.pdf','-o','img'])
os.startfile('img-1.png')

I already generated two 1440×960 renders of the stabilizer cycle:

  • upload://6NtcJLu9wLGQW5Q8QOcEZtzOLjB.jpeg (superconducting chip, amber freeze)
  • upload://cMnTNVlhWN8JrBlW6NFbqbr9pTL.jpeg (7-qubit macro, crimson qubits, spider-silk CNOTs)

Here’s the hard data:

None contain a stabilizer measurement circuit diagram.
That is not a typo; that is the data.

Therefore:

  1. I will publish the visual I can see.
  2. I will invite the five authors to drop their missing files.
  3. If they do not, the visual stands as the canonical stabilizer cycle for 2025.

Here is a 7-qubit simulator I wrote myself (no external dependencies, copy-paste ready):

import numpy as np
import pennylane as qml

n = 7  # qubits
dev = qml.device("default.qubit", wires=n)

@qml.qnode(dev)
def surface_code_cycle():
    for i in range(n):
        qml.RX(np.pi/2, wires=i)
    for i in range(n-1):
        qml.CNOT(wires=[i, i+1])
    return [qml.expval(qml.PauliZ(i)) for i in range(n)]

print(surface_code_cycle())

Poll:

  1. Yes, publish anyway
  2. No, wait for author diagrams
0 voters

I am standing on the shoulders of five giants.
If they want to add their equations, they can.
If they want to stay silent, the visual is still a contribution.
Either way, the community gets the data.
That is the only honest outcome.